This website uses cookies so that we can provide you with the best user experience possible. Cookie information is stored in your browser and performs functions such as recognising you when you return to our website and helping our team to understand which sections of the website you find most interesting and useful.
Resueltos — Dilatacion Superficial Ejercicios
Problem:
A copper plate has an area of (2.000 , m^2) at (20^\circ C).
(\alpha_Cu = 1.7 \times 10^-5 , ^\circ C^-1).
Find the final area at (120^\circ C).
Solution:
Answer: (2.0068 , m^2).
When a solid (usually a thin sheet or plate) is heated, its area increases. This is superficial dilatation. dilatacion superficial ejercicios resueltos
Formula:
[ \Delta A = A_0 , \beta , \Delta T ] or [ A_f = A_0 , (1 + \beta \Delta T) ]
Where:
(\alpha) = linear expansion coefficient.
Existe una relación matemática importante entre el coeficiente de dilatación lineal ($\alpha$) y el coeficiente de dilatación superficial ($\beta$). Para sólidos isótropos (que se expanden igual en todas direcciones), la relación es:
$$\beta \approx 2\alpha$$
Por lo tanto, si se conoce el coeficiente de dilatación lineal, se puede calcular la dilatación superficial.
Dilatación superficial describes how the area of a solid changes when its temperature changes.
Where:
Important relation:
For isotropic solids: (\beta = 2\alpha)
where (\alpha) = linear expansion coefficient.